If I have a URL that, when submitted in a web browser, pops up a dialog box to save a zip file, how would I go about catching and downloading this zip file in Python?
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6 Answers
Batteries included: Download, unzip and parse in 13 lines. 2013-03-31 python, zip, zipfile, csv, urllib, terse. The other day I needed to download some zip files,. Python provides several ways to download files from the internet. This can be done over HTTP using the urllib package or the requests library. This tutorial will discuss how to use these libraries to download files from URLs using Python. The requests library is one of the most popular libraries in Python. I have a remote zip file that contains a.txt file. I need to download and parse some of the data. Python script to download and unzip file. Python, Perl and Golang.
Use urllib2.urlopen. The return value is a file-like object that you can read(), pass to zipfile and so on.
As far as I can tell, the proper way to do this is:
of course you'd want to check that the GET was successful with r.ok.
For python 3+, sub the StringIO module with the io module and use BytesIO instead of StringIO: Here are release notes that mention this change.
With the help of this blog post, I've got it working with just requests. The point of the weird stream thing is so we don't need to call content on large requests, which would require it to all be processed at once, clogging the memory. The stream avoids this by iterating through the data one chunk at a time.
Either use urllib2.urlopen, or you could try using the excellent Requests module and avoid urllib2 headaches:
Thanks to @yoavram for the above solution, my url path linked to a zipped folder, and encounter an error of BADZipfile (file is not a zip file), and it was strange if I tried several times it retrieve the url and unzipped it all of sudden so I amend the solution a little bit. using the is_zipfile method as per here
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Unzip With Python
If I have a URL that, when submitted in a web browser, pops up a dialog box to save a zip file, how would I go about catching and downloading this zip file in Python?
6 Answers
Use urllib2.urlopen. The return value is a file-like object that you can read(), pass to zipfile and so on.
As far as I can tell, the proper way to do this is:
of course you'd want to check that the GET was successful with r.ok.
For python 3+, sub the StringIO module with the io module and use BytesIO instead of StringIO: Here are release notes that mention this change.
With the help of this blog post, I've got it working with just requests. The point of the weird stream thing is so we don't need to call content on large requests, which would require it to all be processed at once, clogging the memory. The stream avoids this by iterating through the data one chunk at a time.
Python Download Zip File
Either use urllib2.urlopen, or you could try using the excellent Requests module and avoid urllib2 headaches:
Download Zip File Opener
How To Download Zip File
Thanks to @yoavram for the above solution, my url path linked to a zipped folder, and encounter an error of BADZipfile (file is not a zip file), and it was strange if I tried several times it retrieve the url and unzipped it all of sudden so I amend the solution a little bit. using the is_zipfile method as per here
Python Unzip File In Memory
